Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Practice Exercises - Page 100: 5

Answer

$4$

Work Step by Step

Given $\lim_{x\to 0}\frac{4-g(x)}{x}=1$, we have $\lim_{x\to 0}(4-g(x))=1\times\lim_{x\to 0}x=0$, thus we have $\lim_{x\to 0}g(x)=4$
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