Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 16: Integrals and Vector Fields - Section 16.8 - The Divergence Theorem and a Unified Theory - Exercises 16.8 - Page 1025: 4

Answer

$$0$$

Work Step by Step

We know that $$ div F=\dfrac{\partial P}{\partial x}i+\dfrac{\partial Q}{\partial y}j $$ From the given equation, we have $ div F=\dfrac{\partial}{\partial x}[0]+\dfrac{\partial}{\partial y} [0]+\dfrac{\partial}{\partial z} [(a^2-x^2-y^2)] \\ =0$
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