#### Answer

Not Conservative

#### Work Step by Step

As we know that $\text{curl} F =(\dfrac{\partial R}{\partial y}-\dfrac{\partial Q}{\partial z})i +(\dfrac{\partial P}{\partial z}-\dfrac{\partial R}{\partial x}) k+(\dfrac{\partial Q}{\partial x}-\dfrac{\partial P}{\partial y})k $
A vector field is conservative iff the $\text{curl} F =0$
Given: $F=y i+(x+z) j-y k$
Now, curl F$=(-1-1) i+(0-0)j +(1-1) k=-2i \ne 0$
This shows that the vector field is Not Conservative