Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 15: Multiple Integrals - Section 15.7 - Triple Integrals in Cylindrical and Spherical Coordinates - Exercises 15.7 - Page 921: 53

Answer

$\frac{\pi}{2}$

Work Step by Step

$ V=4\int^{\pi/2}_0 \int^1_0 \int^{r^2}_0 dz r dr d\theta$ =$4\int^{\pi/2}_0 \int^1_0 r^3 drd\theta $ =$\int^{\pi/2}_0 d\theta $ =$\frac{\pi}{2}$
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