## Thomas' Calculus 13th Edition

$\frac{9}{4}$
$V=\int^{2\pi}_{3\pi/2} \int^{3cos\theta}_0 \int^{-rsin\theta}_0 dz$ r dr $d\theta$ =$\int^{2\pi}_{3\pi/2} \int^{3cos\theta}_0(-r^2\sin\theta) dr d\theta$ =$\int^{2\pi}_{3\pi/2} (-9cos^3\theta)(sin\theta)$ d\theta =$[\frac{9}{4}cos^4\theta]^{2\pi}_{3\pi/2}$ =$\frac{9}{4}-0$ =$\frac{9}{4}$