Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 14: Partial Derivatives - Section 14.7 - Extreme Values and saddle Points - Exercises 14.7 - Page 843: 32

Answer

the absolute maximum is 17 at (0, 4) and (4, 4), and the absolute minimum is 1 at (0, 0).

Work Step by Step

(i) On 2 OA D x y D y y , ( , ) (0, ) 1 on 0 4; y D y y y D (0, ) 2 0 0; (0, 0) 1 and D(0, 4) 17 (ii) On 2 AB D x y D x x x , ( , ) ( , 4) 4 17 on 0 4; ( , 4) 2 4 0 2 x D x x x and (2, 4) is an interior point of ; (2, 4) 13 AB D and D D (4, 4) (0, 4) 17 (iii) On 2 OB D x y D x x x , ( , ) ( , ) 1 on 0 4; x ( , ) 2 0 0 D x x x x and y 0, which is not an interior point of OB; endpoint values have been found above (iv) For interior points of the triangular region, ( , ) 2 0 xf x y x y and ( , ) 2 0 0 yf x y x y x and y 0, which is not an interior point of the region. Therefore, the absolute maximum is 17 at (0, 4) and (4, 4), and the absolute minimum is 1 at (0, 0).
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