Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 14: Partial Derivatives - Section 14.1 - Functions of Several Variables - Exercises 14.1 - Page 787: 3


a. $\frac{4}{5}$ b. $8/5$ c. $3$ d. $0$

Work Step by Step

Plug in each variable into the function and evaluate, as each point is in the form of (x, y, z): a. $\frac{3-(-1)}{(-1)^2+(2)^2}=\frac{4}{5}$ b. $\frac{1-1/2}{(1/2)^2+(-1/4)^2}=\frac{1/2}{5/16}=8/5$ c. $\frac{0-(-1/3)}{(-1/3)^2+(0)^2}=\frac{1/3}{1/9}=3$ d. $\frac{2-2}{(2)^2+(100)^2}=0$
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