Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.6 - Cylinders and Quadric Surfaces - Exercises 12.6 - Page 732: 32

Answer

Hyperbollic paraboloid.
1577315763

Work Step by Step

The form of the equation is $\displaystyle \frac{x^{2}}{1^{2}}-\frac{y^{2}}{1^{2}}=\frac{z}{1},\quad $ this is a Hyperbollic paraboloid (when comparing to Table 12.1). The cross sections with planes $x=k , y=k$ are parabolas, and the cross section with planes $z=k$ are hyperbolas.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.