Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.6 - Cylinders and Quadric Surfaces - Exercises 12.6 - Page 732: 1

Answer

An ellipsoid of revolution as shown in graph (d).

Work Step by Step

Given: $x^2+y^2+4z^2=10$ ...(1) Re-arrange as: $\dfrac{x^2}{(\sqrt{10})^2}+\dfrac{y^2}{(\sqrt{10})^2}+\dfrac{z^2}{(\sqrt{10}/2)^2}=1$ $...(2)$ Hence, the equation (2) shows a graph for An ellipsoid of revolution as shown in graph (d).
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