Answer
$x=t,y=-7+2t, z=2t$
Work Step by Step
As we know the parametric equations of a straight line for a vector $v=v_1i+v_2j+v_3k$ passing through a point $P(a,b,c)$ is given by
$x=a+t v_1,y=b+t v_2; z=c+t v_3$
Since, we have $P=(0,-7,0)$ and $v=\lt 1,2,2 \gt$
Our parametric equations are:
$x=0+(1)t,y=-7+2t, z=0+2t$
Thus, $x=t,y=-7+2t, z=2t$
