Answer
$x=3+2t,y=-2-t, z=1+3t$
Work Step by Step
As we know the parametric equations of a straight line for a vector $v=v_1i+v_2j+v_3k$ passing through a point $P(a,b,c)$ is given by
$x=a+t v_1,y=b+t v_2; z=c+t v_3$
Since, we have $P(3,-2,1)$ and $v=\lt 2,-1,3 \gt$
Our parametric equations are:
$x=3+2t,y=-2-t, z=1+3t$
