Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.4 - The Cross Product - Exercises 12.4 - Page 718: 12

Answer

${\bf( 2i-j)}\times{\bf (i+2j)}=5{\bf k}$
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Work Step by Step

${\bf u}\times{\bf v}=\left|\begin{array}{lll} {\bf i} & {\bf j} & {\bf k}\\ u_{1} & u_{2} & u_{3}\\ v_{1} & v_{2} & v_{3} \end{array}\right|$ --- ${\bf( 2i-j)}\times{\bf (i+2j)}=\left|\begin{array}{rrr} {\bf i} & {\bf j} & {\bf k}\\ 2 & -1 & 0\\ 1 & 2 & 0 \end{array}\right|=(0)-(0)+(4+1){\bf k}$ $=5{\bf k}$
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