Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Section 10.4 - Comparison Tests - Exercises 10.4 - Page 592: 59

Answer

Diverges

Work Step by Step

Given: $\lim\limits_{n \to \infty} a_n=\infty$ In order to define this series, we will take the help of n-th term test. This test states that when $\lim\limits_{n \to \infty} a_n \ne 0$, the series $\Sigma_{n=1}^{\infty} a_n$ diverges. Hence, the given series $\Sigma _{n=1}^\infty a_n$ diverges by n-the term test of divergence.
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