Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Section 10.4 - Comparison Tests - Exercises 10.4 - Page 591: 57

Answer

Convergent

Work Step by Step

Given: $\Sigma a_n$ is convergent. Also, $\Sigma a_n \gt 0$ and $\Sigma b_n \gt 0$ This implies that $\lim\limits_{n \to \infty} \dfrac{a_n}{b_n} =\infty$ Thus, we can see that the series $\Sigma b_n$ is a convergent series by the limit comparison test. Therefore, the series $\Sigma b_n$ is convergent.
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