Answer
$n \gt 10^{60}$
Work Step by Step
Consider $\int_n^\infty \dfrac{1}{x^{(1.1)}}dx \lt 0.00001$
and $ \lim\limits_{k \to \infty} [\dfrac{(-10)}{k^{(0.1)}}+\dfrac{(10)}{n^{(0.1)}} ]\lt 0.00001$
Thus, $\dfrac{10}{n^{(0.1)}} \lt 0.00001 \implies n \gt (10^6)^{10}$
Therefore, $n \gt 10^{60}$
