Answer
$8 m^2$
Work Step by Step
Here, area $A=2^2+(\sqrt 2)^2+(1)^2+(\dfrac{1}{\sqrt 2})^2+....$
or, $A=4+2+1+\dfrac{1}{2}$
or, $A=\dfrac{4}{1-(\dfrac{1}{2})}$
or, $A=8 m^2$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 10: Infinite Sequences and Series - Section 10.2 - Infinite Series - Exercises 10.2 - Page 581: 92
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
