Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.4 - Graphing with Software - Exercises 1.4 - Page 35: 32

Answer

See the graph below.

Work Step by Step

The hyperbola $y^2-\frac{x^2}{1/16}=1$ is centered at the origin with $a=1, b=\frac{1}{4}$; its upper branch will satisfy the condition $y\geq0$ as shown in the figure.
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