Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.3 - Trigonometric Functions - Exercises 1.3 - Page 29: 63



Work Step by Step

We first calculate the third angle $ C=\pi-A-B=\pi-\frac{\pi}{4}-\frac{\pi}{3}=\frac{5\pi}{12}$ Next we use the law of sines $\frac{a}{sinA}=\frac{c}{sinC}$, which leads to $ a=\frac{c\cdot sinA}{sinC}=\frac{2sin\pi/4}{sin5\pi/12}=1.46$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.