Answer
The arc should be $8.4in$ long.
Work Step by Step
$\theta = 80^\circ=\frac{80}{180}\pi=\frac{4}{9}\pi$
$D=12in$
$r=\frac{D}{2}=6in$
$s=r\theta = \frac{4}{9}\pi*6in\approx 8.4in$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 1: Functions - Section 1.3 - Trigonometric Functions - Exercises 1.3 - Page 27: 3
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