Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.1 - Functions and Their Graphs - Exercises 1.1 - Page 13: 60

Answer

$4000~joules $

Work Step by Step

$ K=cv^{2}$ and $ c=\frac{1}{2}m $ (where m is the mass and c is a constant in this problem). When $ v=18m/sec $, $ K=12960joules $, we have $ c=\frac{12960}{18^{2}}=40joules\cdot sec^{2}/m^{2}$ Therefore, when $ v=10m/sec, K=40\times 10^{2}=4000joules $
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