Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Practice Exercises - Page 36: 1

Answer

$ A=\frac{C^2}{4\pi}$

Work Step by Step

Let $ r $ be the radius of a circle; the area $ A $ and circumference $ C $ are: $ A=\pi r^2$ and $ C=2\pi r $. Rewrite the second equation as $ r=\frac{C}{2\pi}$ Plug it into the first one: $ A=\pi\times(\frac{C}{2\pi})^2=\frac{C^2}{4\pi}$
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