Answer
$\lt ln(y-2z),\frac{x}{(y-2z)},-\frac{2x}{(y-2z)}\gt$
Work Step by Step
$f_x(x,y,z)=ln(y-2z)$
$f_y(x,y,z)=\frac{x}{(y-2z)}$
$f_z(x,y,z)=-\frac{2x}{(y-2z)}$
Gradient vector field of $f$ is: $\lt ln(y-2z),\frac{x}{(y-2z)},-\frac{2x}{(y-2z)}\gt$
