Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 11 - Infinite Sequences and Series - 11.2 Exercises: 3

Answer

$\Sigma^{\infty}_{n=1}a_{n}=2$

Work Step by Step

$s_{n} = 2-3(0 \times 8)^{n}$ $\lim\limits_{n \to \infty}s_{n} = \lim\limits_{n \to \infty}(2-3(0.8)^{n})$ $=\lim\limits_{n \to \infty}(2)-3 \times \lim\limits_{n \to \infty} (0.8)^{n}$ $=2-3(0)$ $=2$ $\Sigma^{\infty}_{n=1}a_{n}=2$
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