Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.2 - Exponential Functions and Models - Exercises - Page 643: 60

Answer

$y=1.3867\left(1.4422^{x}\right)$

Work Step by Step

The exponential function we want has the form $y=Ab^{x}$. $\left[\begin{array}{ll} \text{point on} & \text{corresponding}\\ \text{the graph} & \text{equation}\\ (1,2) & 2=Ab^{1}\\ (4,6) & 6=Ab^{4} \end{array}\right]$ Dividing the equations, $\displaystyle \frac{6}{2}=\frac{Ab^{4}}{Ab^{1}}$ $3=b^{2}$, so $b=\sqrt{3}\approx 1.4422$ Back-substituting into the second equation, $2=A(1.4422)^{1}$ $A=\displaystyle \frac{2}{1.4422}\approx 1.3867$ The model is $y=Ab^{x}=1.3867\left(1.4422^{x}\right)$
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