Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Review - Review Exercises - Page 672: 21

Answer

$x=\displaystyle \frac{1}{3}\log 1.05$

Work Step by Step

The base $b$ logarithm of $x,\log_{b}x,$ is the power to which we need to raise $b$ in order to get $x$ . Symbolically, $\quad \log_{b}x=y\quad $ means $\quad b^{y}=x$ --- $300(10^{3x})=315\qquad/\div 300$ $ 10^{3x}=1.05\qquad$... which means $\ \ 3x=\log 1.05$ Divide the last equation with 3, $x=\displaystyle \frac{1}{3}\log 1.05$
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