Answer
${{\$}} 7794.07$
Work Step by Step
The amount A
after investing P dollars at rate r annual interest,
compounded m times a year, for a period of t years is
$A=P\displaystyle \left(1+\frac{r}{m}\right)^{mt}$
Given
$A=10,000,\ r=0.025,\ m=4$, $t=10$
we solve for P:
$10,000=P(1+\displaystyle \frac{0.025}{4})^{40}$
$P=\displaystyle \frac{10,000}{(1+\frac{0.025}{4})^{40}}\approx{{\$}} 7794.07$
