Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Review - Review Exercises - Page 671: 4

Answer

$g$ is exponential, $f$ is not. $g(x)=3(2^{x})$

Work Step by Step

Exponential models have form: $y=Ab^{x}$ When $x$ increases by one unit, the value of$ f$ is multiplied by $b.$ $A=f(0)$ --- When x changes from 1 to 2, f is halved, but, when it changes from -1 to 0, it is not halved. A b described above does not exist, f is not exponential. When $x$ increases by one unit, the value of $ g$ is doubled (multiplied by $b=2$), so $g$ is exponential. since $A=g(0)=3,$ the exponential model is $g(x)=3(2^{x})$
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