Answer
$=\left[\begin{array}{ccc}
-2+x & 0 & 1+w\\
-5+z & 3+r & -2
\end{array}\right]$
Work Step by Step
$A=\left[\begin{array}{lll}
1 & -1 & 0\\
0 & 2 & 1
\end{array}\right],\quad B=\left[\begin{array}{lll}
3 & 0 & -1\\
5 & -1 & 1
\end{array}\right],\quad C=\left[\begin{array}{lll}
x & 1 & w\\
z & r & 4
\end{array}\right]$
$(A-B+C)_{ij}=a_{ij}-b_{ij}+c_{ij}$
---
$A-B+C=\left[\begin{array}{lll}
1-3+x & -1-0+1 & 0-(-1)+w\\
0-5+z & 2-(-1)+r & 1+1-4
\end{array}\right]$
