Answer
$\left[\begin{array}{rr}
-0.75 & -1\\
0 & -0.5\\
-1 & 6
\end{array}\right]$
Work Step by Step
$A=\left[\begin{array}{ll}
0 & -1\\
1 & 0\\
-1 & 2
\end{array}\right], \quad B=\left[\begin{array}{ll}
0.25 & -1\\
0 & 0.5\\
-1 & 3
\end{array}\right],\quad C=\left[\begin{array}{ll}
1 & -1\\
1 & 1\\
-1 & -1
\end{array}\right]$.
$(A+B-C)_{ij}=A_{ij}+B_{ij}-C_{ij}$
$A+B-C=\left[\begin{array}{ll}
0+0.25-1 & -1+(-1)-(-1)\\
1+0-1 & 0+0.5-1\\
-1+(-1)-(-1) & 2+3-(-1)
\end{array}\right]=\left[\begin{array}{ll}
-0.75 & -1\\
0 & -0.5\\
-1 & 6
\end{array}\right]$