Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 13 - Section 13.1 - The Indefinite Integral - Exercises - Page 959: 51b

Answer

$83$ million

Work Step by Step

Midway through the year 2008 is $t=3.5$ years after the start of 2005. $M(3.5)=0.8(3.5)^{4}-6(3.5)^{2}+10(3.5)+1$ $=82.55$ million, Rounded to the nearest million: $83$ million
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