Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 10 - Section 10.5 - Derivatives: Numerical and Graphical Viewpoints - Exercises - Page 753: 39

Answer

$-1.5$

Work Step by Step

We can calculate an approximate value of $f^{\prime}(a)$ by using the formula $f^{\prime}(a)\displaystyle \approx\frac{f(a+h)-f(a)}{h}$ (Rate of change over $[a,\ a+h]$ with a small value of $h$. ) The value $h=0.0001$ works for most examples we encounter. ------------- Evaluate $\displaystyle \frac{f(a+h)-f(a)}{h}$ for a=$-1$, h=$0.0001$ $\displaystyle \frac{f(-0.9999)-f(1)}{0.0001}=\frac{\frac{(-0.9999)^{2}}{4}-\frac{(-0.9999)^{3}}{3} -(\frac{1}{4}-\frac{1}{3})}{}$ ...calculator... $\approx-1.49987500333$ $\approx-1.5$
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