Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 10 - Section 10.4 - Average Rate of Change - Exercises - Page 732: 29b

Answer

$2004-2006$

Work Step by Step

Average rate of change of $f\ \ $ over $[0,2]$ is $\displaystyle \frac{f(2)-f(0)}{2-0}=\frac{4-3}{2}=\frac{1}{2}=0.5$ percentage points per year Average rate of change of $f\ \ $ over $[2,4]$ is $\displaystyle \frac{f(4)-f(2)}{4-2}=\frac{8-4}{2}=\frac{4}{2}=2.0$ percentage points per year Average rate of change of $f\ \ $ over $[4,6]$ is $\displaystyle \frac{f(6)-f(4)}{6-4}=\frac{13-8}{2}=\frac{5}{2}=2.5$ percentage points per year Average rate of change of $f\ \ $ over $[6,8]$ is $\displaystyle \frac{f(8)-f(6)}{8-6}=\frac{13.8-13}{2}=\frac{0.8}{2}=0.4$ percentage points per year The average rate of change was the greatest over $[4,6]$, which corresponds to the $2004-2006$ two-year period.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.