Answer
$f(0)=-1$
Work Step by Step
$\lim\limits_{x \to 0}\frac{x}{3x^2-x}=\lim\limits_{x \to 0}\frac{x}{x(3x-1)}=\lim\limits_{x \to 0}\frac{1}{3x-1}=\frac{1}{3(0)-1}=-1$
Define $f(0)=-1$
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