Answer
$f(-1)=1$
Work Step by Step
$\lim\limits_{x \to -1}\frac{x^2+3x+2}{x+1}=\lim\limits_{x \to -1}\frac{(x+1)(x+2)}{x+1}=\lim\limits_{x \to -1}(x+2)=1$
Define $f(-1)=1$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 10 - Section 10.2 - Limits and Continuity - Exercises - Page 707: 18
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