Answer
$\displaystyle \lim_{t\rightarrow\infty}\frac{E(t)}{I(t)}=0.4 $
Although $E(t)$ rises indefinitely, it remains $2.5$ times smaller than $I(t)$.
Work Step by Step
$t$ is "approaching $+\infty$" means that $t$ is assuming positive values of greater and greater magnitude.
Observe the table below:
As $t$ assumes positive values of greater and greater magnitude, the function value $E(t)$ rises without bound.
So, we write
$\displaystyle \lim_{t\rightarrow\infty}E(t)=\infty.$
The ratio, however, approaches the value $0.4.$
$\displaystyle \lim_{t\rightarrow\infty}\frac{E(t)}{I(t)}=0.4$
$0.4=\displaystyle \frac{1}{2.5}$
Thus, we see that although $E(t)$ rises indefinitely, it remains $2.5$ times smaller than $I(t)$.
