Answer
$\lim\limits_{x \to \ -1}\frac{x^2-9}{2x-6}=\frac{(-1)^2-9}{2(-1)-6}=\frac{-8}{-8}=1$
Work Step by Step
If we want to calculate the value of $\lim\limits_{x \to \ -1}\frac{x^2-9}{2x-6}$,
Here, we can use the formula of:
$\lim \limits_{x\to a}f(x)=f(a)$, meaning that:
$\lim\limits_{x \to \ -1}\frac{x^2-9}{2x-6}=\frac{(-1)^2-9}{2(-1)-6}=\frac{-8}{-8}=1$
