## Finite Math and Applied Calculus (6th Edition)

m=$\displaystyle \frac{3}{2}$, fill y = 7
From the two points ($-2.,4)$ and $(2,10)$ $m=\displaystyle \frac{\Delta y}{\Delta x}=\frac{Change\ in\ y}{Change\ in\ x}=\frac{10-4}{2-(-2)}=\frac{6}{4}=\frac{3}{2}$, which we read also as: "for a change of x of +2, y changes by +3" (rise and run) So, when x changes from $-2$ to $0$, y will change from $4$ to 7. We get (0,7)