Answer
please see image:
Work Step by Step
First objective: write the equation in the form $y=mx+b$;
$3x=-2y$
$-2y=3x\qquad/\div(-2)$
$y=\displaystyle \frac{-3}{2}x$
from where we read:
slope =$\displaystyle \frac{-3}{2}$, y-intercept = 0.
Now,
1. Plot the point $(0,0)$.
2. Using $m=\displaystyle \frac{\Delta y}{\Delta x} =\displaystyle \frac{Rise}{Run}=\frac{-3}{2}$,
for a change in x of $2$,
y changes by $-3$,
which leads us to the point $(0+2,0-3)=(2,-3)$
We now have two points...
.
Draw a straight line through $(0,0)$ and $(2,-3)$.
