Answer
$x_{1}=-1$
$x_{2}=-2$
$x_{3}=-3$
Work Step by Step
$x^3+6x^2+11x+6=0$
$x^3+5x^2+6x+x^2+5x+6=x(x^2+5x+6)+1(x^2+5x+6)=(x+1)(x^2+5x+6)$
$(x+1)(x^2+5x+6)=(x+1)(x^2+3x+2x+6)=(x+1)(x(x+3)+2(x+3))=(x+1)(x+2)(x+3)$
The possible real solutions of the equation of
$(x+1)(x+2)(x+3)=0$ are:
$x_{1}=-1$
$x_{2}=-2$
$x_{3}=-3$
