Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.5 - Solving Polynomial Equations - Exercises - Page 30: 24



Work Step by Step

$16x^{2}=-24x-9$ $16x^{2}+24x+9=0$ $(16x^{2}+12x)+(12x+9)=0$ $4x(4x+3)+3(4x+3)=0$ $(4x+3)(4x+3)=0$ $4x+3=0$ $4x=-3$ $x=-\frac{3}{4}$
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