Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.3 Rational Expressions - R.3 Exercises: 3

Answer

$\dfrac{8}{9}$

Work Step by Step

Simplify by factoring the numerator and the denominator then cancelling common factors to have: $\require{cancel} \\=\dfrac{8(k+2)}{9(k+2)} \\=\dfrac{8\cancel{(k+2)}}{9\cancel{(k+2)}} \\=\dfrac{8}{9}$
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