## Calculus with Applications (10th Edition)

$\displaystyle \frac{3k}{5}$
$\displaystyle \frac{9k^{2}}{25}\cdot \displaystyle \frac{5}{3k}= \qquad$... apply property: $\displaystyle \frac{P}{Q}\cdot\frac{R}{S}=\frac{PR}{QS}$ Write 9 as $3\cdot 3$, 25 as $5\cdot 5$ ( we will reduce what we can) =$\displaystyle \frac{3\cdot 3\cdot 5k^{2}}{5\cdot 5\cdot 3k}= \qquad$... reduce: 3, 5, k $= \displaystyle \frac{3k}{5}$