Answer
$\approx 1.2206$
Work Step by Step
Use the formula for average value with a = 1, and b = e. The average price is: $\frac{1}{e-1}\int^{e}_{1}(x\ln x)dx=\frac{1}{e-1}.(\frac{x^{2}\ln x}{2}-\frac{x^{2}}{4})|^{e}_{1}\approx 1.2206$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 8 - Further Techniques and Applications of Integration - 8.2 Volume and Average Value - 8.2 Exercises - Page 440: 30
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