Answer
$$
f(x)=x^{2}+10x-9
$$
The graph $f(x)$ is always concave upward for all $x$.
$f(x)$ has no inflection points.
Work Step by Step
$$
f(x)=x^{2}+10x-9
$$
The first derivative is
$$
f^{\prime}(x)=2x+10,
$$
and the second derivative is
$$
f^{\prime\prime}(x)=2,
$$
We see that $f^{\prime\prime}(x) \gt 0$ for all $x$, so, $f(x)$ is concave upward for all $x$.
Since $f(x)$ is always concave upward, however, so it has no inflection points.
