Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 4 - Calculating the Derivative - 4.3 The Chain Rule - 4.3 Exercises - Page 226: 55

Answer

$ a.\quad \$ 101.22$ $ b.\quad \$ 111.86$ $ c.\quad \$ 117.59$

Work Step by Step

The rate of change of $A$ with respect to $r$ is $\displaystyle \frac{dA}{dr}$. To find $\displaystyle \frac{dA}{dr}$, we use the chain rule \begin{align*} A(r)&=1500(1+\displaystyle \frac{r}{36,500}]^{1825} \quad & \\\\ \displaystyle \frac{dA}{dr}&= 1500\cdot 1825 [1+\displaystyle \frac{r}{36,500}]^{1824}\cdot [1+\frac{r}{36,500}]^{\prime}\quad & \\ &= 1500\cdot 1825 [1+\displaystyle \frac{r}{36,500}]^{1824}[\frac{1}{36,500}] \quad & \\ &=\displaystyle \frac{ 1500\cdot 1825}{36,500} [1+\frac{r}{36,500}]^{1824}\quad & \\ &=75[1+\displaystyle \frac{r}{36_{9}500}]^{1824} \end{align*} (a) For $r=6\%,$ $\displaystyle \frac{dA}{dr}=75(1+\frac{6}{36,500}]^{1824}= \$ 101.22.$ (b) For $r=8\%,$ $\displaystyle \frac{dA}{dr}=75(1+\frac{8}{36,500}]^{1824}= \$ 111.86.$ (c) For $r=9\%,$ $\displaystyle \frac{dA}{dr}=75(1+\frac{9}{36,500}]^{1824}= \$ 117.59.$
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