Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 3 - The Derivative - 3.3 Rates of Change - 3.3 Exercises - Page 158: 15

Answer

2

Work Step by Step

For x = 0 the instantaneous rate of change is $\lim\limits_{h \to 0} \frac{x(0 + h) - s(0)}{h}$ $x(0+h)=(0+h)^{2}+2(0+h)=h^{2}+2h$ $x(0) = 0$ The instantaneous rate of change is then: $\lim\limits_{h \to 0} \frac{x(0 + h) - s(0)}{h} = \lim\limits_{h \to 0} \frac{h^{2}+2h}{h}=\lim\limits_{h \to 0} 2 = 2$
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