#### Answer

please see "step by step" for explanation

#### Work Step by Step

A limit at x=a exists if
1. both one sided limits exist AND
2. they are equal
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In exercise 6, both
the limit from the left
and the limit from the right exist,
and they both equal 4.
Therefore
$\displaystyle \lim_{x\rightarrow 2}F(x)$ exists and equals 4.
In exercise 9,
the left sided limit exists and equals $-1,$
the right sided limit exists and equals $-\displaystyle \frac{1}{2}$,
BUT, they are not equal, so
$\displaystyle \lim_{x\rightarrow-2}f(x)$ does not exist .