Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.6 Applications: Growth and Decay; Mathematics of Finance - 2.6 Exercises - Page 109: 34

Answer

The half-life of radium-226 is about 1612 years.

Work Step by Step

$$ \begin{aligned} \frac{1}{2} A_{0} &=A_{0} e^{-0.00043 t} \\ & \quad\left[\begin{array}{c}{ \text {Divide by } A_{0}} \end{array}\right] \\ \frac{1}{2} &=e^{-0.00043 t} \\ & \quad\left[\begin{array}{c}{ \text {Take ln of both sides} } \end{array}\right] \\ \ln \frac{1}{2} &=-0.00043 t \\ -\ln 2 &=-0.00043 t \\ t &=\frac{\ln 2}{0.00043} \\ t & \approx 1612 \end{aligned} $$ The half-life of radium 226 is about 1612 years.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.