Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.6 Applications: Growth and Decay; Mathematics of Finance - 2.6 Exercises - Page 109: 33

Answer

The half-life of plutonium-241 is about 13 years.

Work Step by Step

$$ \begin{aligned} \frac{1}{2} A_{0} &=A_{0} e^{-0.053 t} \\ & \quad\left[\begin{array}{c}{ \text {Divide by } A_{0}} \end{array}\right] \\ \frac{1}{2} &=e^{-0.053 t} \\ & \quad\left[\begin{array}{c}{ \text {Take ln of both sides} } \end{array}\right] \\ \ln \frac{1}{2} &=-0.053 t \\ -\ln 2 &=-0.053 t \\ t &=\frac{\ln 2}{0.52} \\ t & \approx 13 \end{aligned} $$ The half-life of plutonium-241 is about 13 years.
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