Answer
$$
y=x^{2}+4x-5
$$
The $x$-intercepts are $1 , -5 $.
The $y$-intercept is -5.
Vertex parabola is $\left(-2 , -9\right)$.
The axis is $x=-2$ , the vertical line through the vertex.
Plotting the vertex, the $y$-intercept,the $x$-intercepts. and the point $\left(-2 , -9\right)$ gives the graph in Figure
Work Step by Step
$$
y=x^{2}+4x-5
$$
The $x$-intercepts can be found by letting $y=0$ to get
$$
y=x^{2}+4x-5=(x+5)(x-1)=0
$$
from which $x=-5 $ and $x=1 $ are the $x$-intercepts.
Set $x=0 $ to find the $y$-intercept.
$$
y=(0)^{2}+4.(0)-5=-5.
$$
So the $y$-intercept is -5.
The $x$-coordinate of the vertex is :
$$
x=\frac{-b}{2a}=\frac{-4}{2}=-2
$$
Substituting this into the equation gives
$$
y=\left(-2\right)^{2}+4\left(-2\right)-5=4-8-5=-9
$$
The vertex is $\left(-2 , -9\right)$.
The axis is $x=-2 $ , the vertical line through the vertex.
Plotting the vertex, the $y$-intercept,the $x$-intercepts. and the point $\left(-2 , -9\right)$ gives the graph in Figure